WEEK:9 PROGRAMMING ASSIGNMENT 2 SOLUTION (Jan 2020-Apr2020) An Introduction to Programming through C++ NPTEL 2020

  

               An Introduction To Programming Through C++

IIT Bombay.

Week 9- Programming Assignment 2:

Write a class Cricketer with following member variables:

char name[100];

int matches;

int innings;

int notOut;

int runs;

double average;

Write member function avg() to calculate average of the cricketer with following rules

1) If the data provided is a mismatch, returned value would be -1

  a) number of matches is less than number of innings

  b) number of notOut is more than number of innings

2) if innings is equal to notOut then avg is the number of runs

3) avg is runs scored divided by the number of innings when the cricketer got out (innings - notOut)

Write another opertor (>) which takes one more Cricketer object as parameter and compares the avg of the two Cricketers. It returns true(1) when the first cricketer's average is more than the Cricketer whose object is passed as parameter, else false(0).

Public Test Cases:

Test Case 1:

Input:

Pravin 100 83 13 4320

Amar 150 137 27 5421

Output:

61.7143 49.2818 1

61.7143 49.2818 1

Passed

Test Case 2:

Input:

Manali 150 137 27 5421

Shefali 100 83 13 4320

Output:

49.2818 61.7143 0

49.2818 61.7143 0

Passed

Test Case 3:

Input:

Ranjit 75 37 47 5421

Praneel 123 125 13 4320

Output:

-1 -1 0

-1 -1 0

Passed

Test Case 4:

Input:

Amin 50 39 39 5421

Sameer 47 43 13 4320

Output:

5421 144 1

5421 144 1

Passed

Test Case 5:

Input:

Sharayu 199 177 27 15421

Shilpa 123 83 43 4320

Output:

102.807 108 0

102.807 108 0

Passed

WRITE/COPY THESE CODE DIRECTLY IN NPTEL TERMINAL AND COMPILE AND RUN THEN SUBMIT.

PROGRAM:

#include<iostream>
using namespace std;


class Cricketer
{
    public: 
    
    char name[100];
 int matches;
 int innings;
 int notOut;
 int runs;
 double average;
  

   double avg()
    {
    
     if(matches<innings||notOut>innings)
       {
         return -1;
       }
     
     if(innings==notOut)
       {
         average=runs;
         return average;
        }
     double n=innings-notOut;
     
     if(n<=innings)
       {
         average=runs/n;
         return average;
       }
}

  int operator >(Cricketer c2)
  {
    int a,b;
    a=average;
    b=c2.average;
    
     if(a==b)
      return 0;
    
     if(average>c2.average)
      return 1;
    else
      return 0;
  }
 
 void read()
 {
   cin>>name>>matches>>innings>>notOut>>runs;
  }
};
 

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