WEEK:10 PROGRAMMING ASSIGNMENT 1 SOLUTION (Jan 2020-Apr2020) An Introduction to Programming through C++ NPTEL 2020

  

               An Introduction To Programming Through C++

IIT Bombay.

Week 10- Programming Assignment 1:

You are required to maintain number of patients infected by corona per country. You are given data which needs to be updated as and when new data is received.

The input line has two parts

1) string: Country, EXIT is specify end of input.

3) int: count

At the end print count per country (sorted by country name). Following is the sample input and expected output.

Input:
China 10

USA 5

China -5

USA -5

China -5

USA 5

EXIT

Output:

China:0

USA:5

Public Test Cases:

Public Test Cases: 3 / 3 Passed

Public Test Cases Input Expected Output Actual Output Status
Test Case 1
China 10
USA 5
China -5
USA -5
China -5
USA 5
EXIT

China:0\n
USA:5\n
China:0\n
USA:5\n
Passed

Test Case 2
Italy 5
China 100
China -10
Spain 20
France 7
Italy 25
India 20
Italy -20
India -10
India 5
India -5
EXIT

China:90\n
France:7\n
India:10\n
Italy:10\n
Spain:20\n
China:90\n
France:7\n
India:10\n
Italy:10\n
Spain:20\n
Passed

Test Case 3
China 100
Italy 5
China 120
Spain 20
France 7
Italy 25
France 0
Italy 40
France 2
Italy 0
EXIT

China:220\n
France:9\n
Italy:70\n
Spain:20\n
China:220\n
France:9\n
Italy:70\n
Spain:20\n
Passed

WRITE/COPY THESE CODE DIRECTLY IN NPTEL TERMINAL AND COMPILE AND RUN THEN SUBMIT.

PROGRAM:

#include <iostream>
#include <string.h>
#include <stdio.h>


using namespace std; 

struct a1
{
 char country[100];
 int count;
};
void swap (a1 &x,a1 &y)
{
 a1 temp;
 temp=x;
 x=y;
 y=temp;
}
 
void sortcountry(a1 x[],int n)
{
 for (int i=0;i<n-1;i++)
  for (int j=i+1;j<n;j++)
   if (strcmp(x[i].country,x[j].country)>0)
    swap(x[i],x[j]);
}
 
void display(a1 x[],int n)
{
    string a2;

 for (int i=0;i<n;i++)
 {
     a2=x[i].country;
     if(a2=="EXIT")
         break;
     cout<<x[i].country<<":"<<x[i].count<<endl;    
 }
}

int arr_len(a1 x[])
{
    string a2;int i;
    for (i=0;i<100;i++)
 {
     a2=x[i].country;
     if(a2=="EXIT")
         break;
 }
 return i;
}

int search(a1 a3[],char a4[],int n)
{
    int i,a5;
    for (i=0;i<n;i++)
 {
     if(strcmp(a4,a3[i].country)==0)
     {
         cin>>a5;
         a3[i].count=a3[i].count+a5;
         
         return 1;
     }
 }
 return 0;
}


int main()
{
 a1 a4[100];
 int n=10;
    char a6[100];
 for (int i=0;;i++)
 {
 cin>>a6;
 if(search(a4,a6,i))
 {
     i=i-1;
     continue;
 }
    strcpy(a4[i].country,a6);
 if(strcmp(a6,"EXIT")==0)
  {   break; a4[i].count=0;}
 cin>>a4[i].count;
 
    }
 
 sortcountry(a4,arr_len(a4));
 display(a4,arr_len(a4));
 return 0;
}
 

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