NPTEL(14 Sep- 06 Nov) | Week 0: Assignment 2 ( Question 1 ,Question 2 & Question 3)Introduction to Programming in C 2020.

        Introduction to Programming in C       

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Assignment 2 ->Question1:

In this assignment, you will be given an NxN matrix. You have to

determine whether the matrix is a upper triangular or lower triangular matrix or both or not a triangular matrix. 

The diagonal of the matrix M of size NxN is the set of entries M(0,0),

M(1,1), M(2,2), ..., M(N,N). 

A matrix is upper triangular if every entry below the diagonal is

0. For example,  

1 1 1

0 0 1

0 0 2

is an upper triangular matrix. (The diagonal itself, and the entries

above can be zeroes or non-zero integers.) 

A matrix is lower triangular if every entry above the diagonal is

0. For example, 

2 0 0

3 1 0

4 2 2

is a lower triangular matrix  (The diagonal itself, and the entries

below can be zeroes or non-zero integers.) . 

A matrix is not a triangular matrix if it is neither a upper triangular nor a  lower

triangular.

You may not use arrays for this program.

Input

First, you will be given N, which is the size of the matrix.

Then you will be given N rows of integers, where each row consists of

N integers separated by spaces. 

Output

If the input matrix is lower triangular, then print -1.

If the input matrix is upper triangular, then print 1.

If the input matrix is both lower and upper triangular, then print 2.

If the input matrix is not a triangular matrix, then print 0.

IF YOU NEED EXPLANATION YOU CAN COMMENT .

PROGRAM:

#include<stdio.h>


int main()
{
  int n,u=0,l=0,t=0,m=0,d=0;
  
  scanf("%d",&n);
  int A[n][n];
  m=n-1;
  for(int i=0;i<n;i++)
  {
    
     for(int j=0;j<n;j++)
     {
         scanf("%d",&A[i][j]);
     }
   
  }
  


   for(int i=0;i<n;i++)
  {
    
     for(int j=0;j<n;j++)
     {
       if(i!=j)
       {
         if(A[i][j]==0)
         t++;
       }  
         if(i>j)
       {
         if(A[i][j]==0)
           u++;
       }  
        if(i<j)
       {
         if(A[i][j]==0)
           l++;
       }  
         
         
     }
   }
  
  if(t==2*n)
    printf("2");
  else if(l==n)
    printf("-1");
  else if(u==n)
    printf("1");
  else
    printf("0");
    
  
  
  
  return 0;
  
}

Assignment 2 ->Question2:

You are given a sorted(either in the increasing or in the decreasing order) sequence of positive numbers, ending with a -1. You can assume that there are atleast three numbers before the ending -1. 

Note : -1 is not a part of input. It only signifies that input has ended.

Let us call the sequence x0  x1 ... xn -1.

You have to output 1 if there are atleast three distinct numbers in the sequence.

otherwise output 0

PROGRAM:

#include<stdio.h>


int main()
{
  int a[100],b[100],i=-1,n=0,k=1;
  
  do
  {
    i++;
    scanf("%d",&a[i]);
 
  }while(a[i]!=-1);



  for(int j=0;a[j]!=-1;j++)
  { b[j]=a[j];
    n++;}
  
    for(int j=1;j<n;j++)
    {
      if(b[j]!=b[j-1])
        k++;
    }
  
  if(k==n)
    printf("1");
  else
    printf("0");
  
  
  
  return 0;
  
}

  WEEK-0 :INTRODUCTION TO PROGRAMMING IN C

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